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653.java
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73 lines (71 loc) · 2.11 KB
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__________________________________________________________________________________________________
sample 1 ms submission
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public boolean findTarget(TreeNode root, int k) {
return traverseNode(root, k, root);
}
private boolean traverseNode(TreeNode node, int k, TreeNode root) {
if (node == null) {
return false;
}
boolean result = node.val * 2 != k ? findTargetNode(root, k-node.val) : false;
return result || traverseNode(node.left, k, root) || traverseNode(node.right, k, root);
}
private boolean findTargetNode(TreeNode node, int n) {
if (node == null) {
return false;
}
if (node.val == n) {
return true;
} else if (node.val < n) {
return findTargetNode(node.right, n);
} else {
return findTargetNode(node.left, n);
}
}
}
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sample 38484 kb submission
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean findTarget(TreeNode root, int k) {
List < Integer > list = new ArrayList();
inorder(root, list);
int l = 0, r = list.size() - 1;
while (l < r) {
int sum = list.get(l) + list.get(r);
if (sum == k)
return true;
if (sum < k)
l++;
else
r--;
}
return false;
}
public void inorder(TreeNode root, List < Integer > list) {
if (root == null)
return;
inorder(root.left, list);
list.add(root.val);
inorder(root.right, list);
}
}
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